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Our Class

Christmas Wishes

Merry Christmas and a Happy New Year to everyone.

Mr.P

Hi Everyone,

I hope everything is going well, and you are learning/getting ready for the exam.
If I get some time I will post couple pictures (perhaps selfies).
Keep up the good work.
Until next type.
From Lousika/Patras, Greece, Europe, World.

Mr. P

Trig Help

Hello there Fellow classmates, Irene here. You all probably know me. Im tiny, but hard to miss. Im not going to make this message long and get to the point. I am posting this because I want to help everybody. The last trig test didn't as I planned. :( After that I was determined to get a better grade. I wanted to get more practice, to be more prepared for the next precal test. So I decided to go to the old precal exams and copy every single question that had the word sin, cos, tan, csc, sec, cot, and everything that relates to trig. I started from June 2013 and went all the way back to January of 2007. I wanted to go all the way to 2004, but sadly I got busy with other things and ran out of time. I hope you will make good use of my endless hours of coping and pasting.

PS I didn't get any questions from booklet one of January 2007 because it was malfunctioning :(


Here's the link
https://www.dropbox.com/s/p9x4m3q0ntwey90/trig%20unit.docx

Hi! Everyone, My name is Shivani. You probably know me, but if you don't I sit right in middle of Harsimran and Ruthanne. Now I shall introduce you with Solving Trigonometric Equations using Identities.


Trignometric Identities are equations involving the trignometric function that are true for every values of the variables involved. Youn can use trignometric identites along with algebric methods to solve trignometric equations.

Example
Find all the solutions of the equation in the interval 2sin²x=2+cosx

The equation contains both sine and cosine functions.
We rewrite the equation so that it contains only cosine functions using the Pythagorean Identity sin²x=1cos²x

Factoring cosx, we get,cosx(2cosx+1)=0

By using zero-product-property,we will get cosx=0,and 2cosx+1=0 whcih yields x= ^-1⁄₂
In the interval [0, 2π), we know that cosx=0 when x=^π⁄₂ and x= ^3π⁄₂ .On the other hand, we also know that cosx= ^-1⁄₂ when x= ^2π⁄₃ and x= ^4π⁄₃
Therefore, the solutions of the given equation in the interval [0, 2π) are { ^π⁄₂,^3π⁄₂,^2π⁄₃,^4π⁄₃}

I hope you've learned something ! And
Good luck for the test. :)

Proving Identities

Hello everybody, my name is Ariana. I am the middle of the 3 ladies who sit at the front table..........probably the one crying (I'm not fully on board and ready to steer this pre-cal ship, so please bear with me on this scribe as I write it while I dangle out, feet soaked in the cold ocean water). If you don't know me by now, feel free to introduce yourself!I I don't bite..... unless necessary :)

Now onto proving identities. Proving an identity is showing how one side of the equation, is the same as the other. (Left Hand Side = Right Hand Side). You can do so by separately simplifying both sides of the identity into identical expressions, Do not attempt to do both at the same time, this process is complicated and prone to much confusion. Also in some cases, you can get both sides identical with only one simplifying one equation. It doesn't matter which side you start with,your best bet is to start with the more complicated one.

As seen in our booklets here are some STRATEGIES (not to be confused with steps) that may help:

• Use known Identities to make substitution ex) tanx=sinx/cosx
• If qaudratics are present, the Pythagorean identity (sin^2theta + cos^2theta=1) or one of its alternate forms can be used. ex) sin^2theta/cos^2theta will become sin^2theta/1-sin^2theta
• Rewrite the expression using only sin and cosine
• Multiply the numerator and the denominator by the conjugate of an expression
• Factor to simplify the expression

Some examples we went over together in class:

Example a)

I apologize for poor quality pictures

Starting with the left hand side (since we cant do anything to the right) the first step would be to change everything we can to sine or cosine.

Based on trig identities we know tantheta would become sintheta/costheta, csctheta would become 1/sintheta.

As we can see in the picture the cos and sin would cancel out, leaving us with only 1

Since 1 is what is on the right we have 1=1, LHS=RHS 

 Example b)

Quality plus my handwriting gets worse...

 On the LHS, first we change everything to become sine or cosine. Cottheta turns into costheta/sintheta and sec^2 becomes 1/cos^theta.

The costheta on the numerator would cancel with one on the denominator (remember that it's squared, we would still be left with one costheta).

Therefore our LHS is left with 1/sintheta costheta

1/ sintheta costheta is what is on the RHS, LHS=RHS

Example c)

In the LHS we convert tan to become sintheta/costheta.

The next step to this equation is to find the common denominator, which is costheta.

Apply the CD and we get sintheta costheta + sintheta/ cos theta.

Our next instinct might be that the costheta would cancel but that would be wrong because of that addition symbol.

The next step would be to factor out sintheta

Leaving us with LHS:  sintheta(costheta+1/costheta)

For the RHS, of course we change to become sin or cosine.

1=sectheta/csctheta becomes *look on pic, for it does not look pretty typed*

Find the common denominator and then I'm pretty sure you already know the steps to simplify further.

The RHS is (costheta+1)sintheta/costheta

LHS=RHS

Example d)

In this special case we start by multiplying by the conjugate. 

According to the Pythagorean identity we can change 1-cos^2 into sin^6.

Need I tell you what to do next?

LHS=RHS

I hope this scribe helped whomever may need extra assistance. Good luck!